Explain how rusting of iron is envisaged as setting up of an electrochemical cell. Chapter 3: Electrochemistry Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 3.15: Explain how rusting of iron is envisaged as setting up of an electrochemical cell. is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 3 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 3: Electrochemistry is very essencial for getting good marks in CBSE Board examinations
Question 3.15: Explain how rusting of iron is envisaged as setting up of an electrochemical cell.
Answer:In process of rusting, water molecules present at the layer of iron react with oxides and get dissociated and give H+ ions
H2O + CO2 → H2CO3
H2CO3 ↔ 2H+ + CO32–
In present of H+ ions iron convert in Fe2+ so this part is act as anode
Reaction at anode:
Fe(s) → Fe2+(aq) + 2e–
Electron released at anodic spot move through the metals and go to another spot on the metal and reduce oxygen this spot act as cathode
Reaction at Cathode:
O2(g) + 4H+(aq) + 4e+( aq) → 2H2O(l)
The overall reaction
2Fe(s) + O2(g) + 4H+(aq) → 2H2O(l) + Fe2+(aq)
Hence, rusting of iron act as electrochemical cell.
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